2014年3月20日星期四

Meilleur Oracle 1z1-061 1z0-061 1Z0-060 1Z1-536J 1Z1-536 test formation guide

Nous assurons seulement le succès de test certification, mais encore la mise à jour est gratuite pour vous. Si vous ne pouvez pas passer le test, votre argent sera 100% rendu. Toutefois, cette possibilité n'est presque pas de se produire. Vous pouvez tout d'abord télécharger le démo gratuit pour prendre un essai.

Le test certification Oracle 1z1-061 1z0-061 1Z0-060 1Z1-536J 1Z1-536 est une bonne preuve de connaissances professionnelles et la techniques. Dans l'Industrie IT, beaucoiup de humains ressource font l'accent de lesquels certificats que les volontiers obtiennent. C'est clairement que le certificat Oracle 1z1-061 1z0-061 1Z0-060 1Z1-536J 1Z1-536 puisse augmenter la compétition dans ce marché.

Beaucoup de gens trouvent difficile à passer le test Oracle 1z1-061 1z0-061 1Z0-060 1Z1-536J 1Z1-536, c'est juste parce que ils n'ont pas bien choisi une bonne Q&A. Vous penserez que le test Oracle 1z1-061 1z0-061 1Z0-060 1Z1-536J 1Z1-536 n'est pas du tout autant dur que l'imaginer. Le produit de Pass4Test non seulement comprend les Q&As qui sont impressionnées par sa grande couverture des Questions, mais aussi le service en ligne et le service après vendre.

Code d'Examen: 1z1-061
Nom d'Examen: Oracle (Oracle Database 12c: SQL Fundamentals)
Questions et réponses: 75 Q&As

Code d'Examen: 1z0-061
Nom d'Examen: Oracle (Oracle Database 12c: SQL Fundamentals)
Questions et réponses: 75 Q&As

Code d'Examen: 1Z0-060
Nom d'Examen: Oracle (Upgrade to Oracle Database 12c)
Questions et réponses: 150 Q&As

Code d'Examen: 1Z1-536J
Nom d'Examen: Oracle (Oracle Exadata 11g Essentials (1Z1-536日本語版))
Questions et réponses: 69 Q&As

Code d'Examen: 1Z1-536
Nom d'Examen: Oracle (Oracle Exadata 11g Essentials)
Questions et réponses: 69 Q&As

Pass4Test peut non seulement vous aider à réussir votre rêve, mais encore vous offre le service gratuit pendand un an après vendre en ligne. Q&A offerte par l'équipe de Pass4Test vous assure à passer 100% le test de Certification Oracle 1z1-061 1z0-061 1Z0-060 1Z1-536J 1Z1-536.

Dans cette société bien intense, c'est avantage si quelque'un a une technique particulère, donc c'est pourquoi beaucoup de gens ont envie de dépnenser les efforts et le temps à préparer le test Oracle 1z1-061 1z0-061 1Z0-060 1Z1-536J 1Z1-536, mais ils ne peuvaient pas réussir finalement. C'est juste parce que ils ont pas bien choisi une bonne formation. L'outil de formation lancé par les experts de Pass4Test vous permet à passer le test Oracle 1z1-061 1z0-061 1Z0-060 1Z1-536J 1Z1-536 coûtant un peu d'argent.

1z0-061 Démo gratuit à télécharger: http://www.pass4test.fr/1z0-061.html

NO.1 View the Exhibit for the structure of the student and faculty tables.
You need to display the faculty name followed by the number of students handled by the faculty at
the base location.
Examine the following two SQL statements:
Which statement is true regarding the outcome?
A. Only statement 1 executes successfully and gives the required result.
B. Only statement 2 executes successfully and gives the required result.
C. Both statements 1 and 2 execute successfully and give different results.
D. Both statements 1 and 2 execute successfully and give the same required result.
Answer: D

Oracle examen   1z0-061 examen   1z0-061   1z0-061

NO.2 Examine the types and examples of relationships that follow:
1.One-to-one a) Teacher to students
2.One-to-many b) Employees to Manager
3.Many-to-one c) Person to SSN
4.Many-to-many d) Customers to products
Which option indicates the correctly matched relationships?
A. 1-a, 2-b, 3-c, and 4-d
B. 1-c, 2-d, 3-a, and 4-b
C. 1-c, 2-a, 3-b, and 4-d
D. 1-d, 2-b, 3-a, and 4-c
Answer: C

Oracle   1z0-061   1z0-061   1z0-061   certification 1z0-061

NO.3 View the Exhibit and evaluate the structure and data in the CUST_STATUS table.
You issue the following SQL statement:
Which statement is true regarding the execution of the above query?
A. It produces an error because the AMT_SPENT column contains a null value.
B. It displays a bonus of 1000 for all customers whose AMT_SPENT is less than CREDIT_LIMIT.
C. It displays a bonus of 1000 for all customers whose AMT_SPENT equals CREDIT_LIMIT, or
AMT_SPENT is null.
D. It produces an error because the TO_NUMBER function must be used to convert the result of the
NULLIF function before it can be used by the NVL2 function.
Answer: C

certification Oracle   1z0-061   certification 1z0-061
Explanation:
The NULLIF Function The NULLIF function tests two terms for equality. If they are equal the function
returns a null, else it returns the first of the two terms tested. The NULLIF function takes two
mandatory parameters of any data type. The syntax is NULLIF(ifunequal, comparison_term), where
the parameters ifunequal and comparison_term are compared. If they are identical, then NULL is
returned. If they differ, the ifunequal parameter is returned.

NO.4 View the Exhibit and examine the structure of the product, component, and PDT_COMP
tables.
In product table, PDTNO is the primary key.
In component table, COMPNO is the primary key.
In PDT_COMP table, <PDTNO, COMPNO) is the primary key, PDTNO is the foreign key referencing
PDTNO in product table and COMPNO is the foreign key referencing the COMPNO in component
table.
You want to generate a report listing the product names and their corresponding component names,
if the component names and product names exist.
Evaluate the following query:
SQL>SELECT pdtno, pdtname, compno, compname
FROM product _____________ pdt_comp
USING (pdtno) ____________ component USING (compno)
WHERE compname IS NOT NULL;
Which combination of joins used in the blanks in the above query gives the correct output?
A. JOIN; JOIN
B. FULL OUTER JOIN; FULL OUTER JOIN
C. RIGHT OUTER JOIN; LEFT OUTER JOIN
D. LEFT OUTER JOIN; RIGHT OUTER JOIN
Answer: C

certification Oracle   1z0-061 examen   1z0-061

NO.5 In the customers table, the CUST_CITY column contains the value 'Paris' for the
CUST_FIRST_NAME 'Abigail'.
Evaluate the following query:
What would be the outcome?
A. Abigail PA
B. Abigail Pa
C. Abigail IS
D. An error message
Answer: B

certification Oracle   certification 1z0-061   1z0-061 examen   1z0-061 examen   1z0-061

NO.6 Evaluate the following SQL statement:
Which statement is true regarding the outcome of the above query?
A. It executes successfully and displays rows in the descending order of PROMO_CATEGORY .
B. It produces an error because positional notation cannot be used in the order by clause with set
operators.
C. It executes successfully but ignores the order by clause because it is not located at the end of the
compound statement.
D. It produces an error because the order by clause should appear only at the end of a compound
query-that is, with the last select statement.
Answer: D

Oracle   1z0-061   1z0-061

NO.7 Examine the structure proposed for the transactions table:
Which two statements are true regarding the creation and storage of data in the above table
structure?
A. The CUST_STATUS column would give an error.
B. The TRANS_VALIDITY column would give an error.
C. The CUST_STATUS column would store exactly one character.
D. The CUST_CREDIT_LIMIT column would not be able to store decimal values.
E. The TRANS_VALIDITY column would have a maximum size of one character.
F. The TRANS_DATE column would be able to store day, month, century, year, hour, minutes,
seconds, and fractions of seconds
Answer: B,C

Oracle examen   1z0-061 examen   1z0-061
Explanation:
VARCHAR2(size)Variable-length character data (A maximum size must be specified:
minimum size is 1; maximum size is 4, 000.)
CHAR [(size)] Fixed-length character data of length size bytes (Default and minimum size
is 1; maximum size is 2, 000.)
NUMBER [(p, s)] Number having precision p and scale s (Precision is the total number of
decimal digits and scale is the number of digits to the right of the decimal point; precision
can range from 1 to 38, and scale can range from -84 to 127.)
DATE Date and time values to the nearest second between January 1, 4712 B.C., and
December 31, 9999 A.D.

NO.8 Which three tasks can be performed using SQL functions built into Oracle Database?
A. Displaying a date in a nondefault format
B. Finding the number of characters in an expression
C. Substituting a character string in a text expression with a specified string
D. Combining more than two columns or expressions into a single column in the output
Answer: A,B,C

certification Oracle   1z0-061   1z0-061

NO.9 Which normal form is a table in if it has no multi-valued attributes and no partial
dependencies?
A. First normal form
B. Second normal form
C. Third normal form
D. Fourth normal form
Answer: B

Oracle examen   certification 1z0-061   certification 1z0-061   certification 1z0-061   1z0-061

NO.10 You need to create a table for a banking application. One of the columns in the table has the
following requirements:
1. You want a column in the table to store the duration of the credit period.
2) The data in the column should be stored in a format such that it can be easily added and
subtracted with date data type without using conversion functions.
3) The maximum period of the credit provision in the application is 30 days.
4) The interest has to be calculated for the number of days an individual has taken a credit for.
Which data type would you use for such a column in the table?
A. DATE
B. NUMBER
C. TIMESTAMP
D. INTERVAL DAY TO SECOND
E. INTERVAL YEAR TO MONTH
Answer: D

Oracle   1z0-061 examen   1z0-061 examen   1z0-061   1z0-061 examen

没有评论:

发表评论